Question

# A particle A is projected from the ground with an initial velocity of 10 m/s at an angle of 60∘ with horizontal. From what height h should an another particle B be projected horizontally with velocity 5 m/s so that both the particles collides at point C if both are projected simultaneously (g=10m/s2)

A
10 m
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B
30 m
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C
15 m
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D
25 m
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Solution

## The correct option is C 15 mGiven, Velocity of 1st projectile, u=10ms−1 Angle of projection, θ=60o Time of flight, t=2usin60og=2×10sin60o10=√3sec Given, Velocity of 2nd projectile in vertical direction, uy=0 Time, t=√3sec Height of fall, s=uyt+12gt2=0+12×10×(√3)2=15m Hence, height is 15m

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