A particle accelerates from rest at a constant rate for sometime and attains a velocity of $8 m / s e c$ . A afterwards it decelerates with constant with the constant rate and comes to rest . If the total time taken is $4 s e c$ , the distance travelled is :

32 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $16 m$
Option b is correct

Suggest Corrections

Similar questions

2 a m / s^{2}

20 m / s

a m / s^{2}

10 s

a l p h a

β

2 m s^{- 2}

4 m s^{- 2}

6 s

Join BYJU'S Learning Program