A particle acted on by constant forces 4^i+^j−3^k and 3^i+^j−^k is displaced from the point (1,2,3) to (5,4,1) the work done is
A
20
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B
30
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C
40
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D
50
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Solution
The correct option is C40 Displacement vector is →s=5^i+4^j+^k−(^i+2^j+3^k) =4^i+2^j−2^k →F=Force vector=4^i+^j−3^k+3^i+^j−^k =7^i+2^j−4^k work done=→F.→S =(7^i+2^j−4^k).(4^i+2^j−2^k) =28+4+8=40