Question

A particle at $x=0$ and $t=0$ starts moving along $+$ve X-direction with velocity v then x varies with time as?

• A. t
• B. $t^3$
• C. $t^2$
• D. $t^{1/2}$

Answer 1

The correct option is A t

We know that, rate of change of displacement = velocity.

=> $\frac{dx}{dt}$= v

dx= v.dt

Integrating both side, ${\int }_o^{x}dx={\int }_0^{t}v.dt$

x-0= v(t-0)

x=vt

Hence, x varies with time linearly.