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Circular Kinematics

A particle ca...

Question

A particle carrying a charge $e$ enters perpendicularly into a uniform magnetic field of induction $B$ with momentum $p$ . Then, the radius of the circular path is

A

\frac{B e}{p}

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B

\frac{p e}{B}

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C

\frac{p}{B e}

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D

B e p

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Solution

The correct option is B $\frac{p}{B e}$
$q v B = \frac{m v^{2}}{R}$
$R = \frac{m v}{B e} = \frac{P}{B e}$ (Charge $q = e$ )

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