A particle describes uniform circular motion in a circle of radius $2 m$ , with the angular speed of $2 r a d s^{- 1}$ . Then magnitude of the change in its velocity in $\frac{π}{2} s$ is

0 m s^{- 1}

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2 \sqrt{2} m s^{- 1}

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8 m s^{- 1}

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4 m s^{- 1}

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4 \sqrt{2} m s^{- 1}

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Solution

The correct option is B $8 m s^{- 1}$
Given:
$w = 2 r a d / s$
$R = 2 m$
$t = π / 2 s$
Angle travelled in time $t$ , $θ = w t = π r a d$
$M a g n i t u d e o f v e l o c t y = w R = 4 m / s$
Change in Velocity , $△ v = v_{f i n a l} - v_{i n i t i a l} = 4 - (- 4) = 8 m / s$

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A particle describes uniform circular motion in a circle of radius 2m, with the angular speed of 2rad s−1. Then magnitude of the change in its velocity in π2s is

The correct option is B 8ms−1Given:w=2rad/sR=2mt=π/2sAngle travelled in time t, θ=wt=πradMagnitudeofvelocty=wR=4m/sChange in Velocity ,△v=vfinal−vinitial=4−(−4)=8m/s

A particle describes uniform circular motion in a circle of radius $2 m$ , with the angular speed of $2 r a d s^{- 1}$ . Then magnitude of the change in its velocity in $\frac{π}{2} s$ is

The correct option is B $8 m s^{- 1}$
Given:
$w = 2 r a d / s$
$R = 2 m$
$t = π / 2 s$
Angle travelled in time $t$ , $θ = w t = π r a d$
$M a g n i t u d e o f v e l o c t y = w R = 4 m / s$
Change in Velocity , $△ v = v_{f i n a l} - v_{i n i t i a l} = 4 - (- 4) = 8 m / s$