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Byju's Answer
Standard XII
Physics
Com of Solid Bodies
A particle ex...
Question
A particle executed SHM according to equations 4d^2x/dt^2 +320x =0 it time period of oscillations
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Q.
The equation of motion of a particle executing SHM is
(
d
2
x
d
t
2
)
+
k
x
=
0
. The time period of the particle will be ?
Q.
Given a differential equation of SHM :
a
d
2
x
d
t
2
+
b
x
=
0
The time period of this oscillation is given by :
Q.
The differential equation for a particle of mass 2kg executing SHM is
2
d
2
x
d
t
2
+
x
=
0
. If amplitude of oscillation is 3 cm, then maximum velocity of the particle will be
Q.
The differential equation representing the SHM of a particule is
9
d
2
y
d
t
2
+ 4y = 0. the time period of the particle is given by
Q.
A particle is executing SHM with time period
T
, starting from mean position. Time taken by it to complete
5
8
th
part of oscillation will be
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