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Question

A particle executes a SHM with frequency ν. The frequency of variation of potential energy will be :


A

2v

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B

v

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C

v/2

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D

3 ν

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Solution

The correct option is A

2v


K.E. and P.E. are square of sinusoidal functions. So the frequency of variation will be double of the frequency of oscillation.


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