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Question

A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is:

A

2π/√3

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B

1/ 2π√3

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C

2π√3

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D

√3/2π

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Solution

The correct option is A
2π/√3

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