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Question

A particle executes S.H.M (a) What fraction of total energy is kinetic? What fraction is potential when displacement is one half of the amplitude?


A

34 and 14

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B

23 and 13

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C

12 and 12

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D

16 and 56

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Solution

The correct option is A

34 and 14


The total energy of a particle doing SHM is 12KA2. NOw at any displacement x from the mean position the P,E is 12kx2 so at this position K.E = T.E - P.E =12KA212kx2
When displacement is half the amplitude
x = A2
P.E=12k(A2)214KA2=14xT.EK.E.=12kA214x12KA2=34x12KA2=34xT.E
So the correct option is (a).


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