A particle executes S.H.M (a) What fraction of total energy is kinetic? What fraction is potential when displacement is one half of the amplitude?
34 and 14
The total energy of a particle doing SHM is 12KA2. NOw at any displacement x from the mean position the P,E is 12kx2 so at this position K.E = T.E - P.E =12KA2−12kx2
When displacement is half the amplitude
x = A2
∴P.E=12k(A2)214KA2=14xT.EK.E.=12kA2−14x12KA2=34x12KA2=34xT.E
So the correct option is (a).