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Question

# A particle executes S.H.M (a) What fraction of total energy is kinetic? What fraction is potential when displacement is one half of the amplitude?

A

34 and 14

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B

23 and 13

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C

12 and 12

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D

16 and 56

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Solution

## The correct option is A 34 and 14 The total energy of a particle doing SHM is 12KA2. NOw at any displacement x from the mean position the P,E is 12kx2 so at this position K.E = T.E - P.E =12KA2−12kx2 When displacement is half the amplitude x = A2 ∴P.E=12k(A2)214KA2=14xT.EK.E.=12kA2−14x12KA2=34x12KA2=34xT.E So the correct option is (a).

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