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Velocity Displacement Relationship

A particle ex...

Question

A particle executes S.H.M. with amplitude of $10 c m$ and period of $10 s$ . Find the (i) velocity, (ii) acceleration of the particle at a distance $5 c m$ from the equilibrium position.

15.442 c m / s

- 1.974 c m / s^{2}

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5.442 c m / s

- 1.974 c m / s^{2}

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5.442 c m / s

- 19.974 c m / s^{2}

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0.442 c m / s

- 0.974 c m / s^{2}

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Solution

The correct option is B $5.442 c m / s$ , $- 1.974 c m / s^{2}$ .

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