A particle executes SHM according to the equation Y=2sin2πt where ‘Y’ is displacement in ‘m’ and ‘t’ is time is ‘seconds’. The distance covered by the particle in 4s of its motion is
A
2m
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B
8m
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C
32m
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Solution
The correct option is C 32m y=Asinωt for one oscillation T = 1sec S = 4A = 8 For 4 sec 4 oscillate Stotal=32m