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Velocity Displacement Relationship

A particle ex...

Question

A particle executes SHM with a period of 16 s. At time t=2s, the particle crosses the mean position while at t=4s, it's velocity is 4 m/s. Amplitude of motion in metre is

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Q. A particle executes SHM with a time period of

16

t = 2 s

, the particle crosses the mean position while at

t = 4 s

, its velocity is

4 m s^{- 1}

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Q. A particle executes SHM with a period of

T

second and amplitude

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metre. The particle is at its mean position initially The shortest time it takes to reach point

\frac{A}{\sqrt{2}}

metre from its mean position in seconds is

Q. A particle executes SHM with a period of

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second and amplitude

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metre. The particle is at its mean position initially. The shortest time it takes to reach point

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Q. A particle executes SHM with an amplitude of

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. When the particle is at

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from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

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. When the particle is at

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from the mean position, the magnitude of its velocity is equal to twice of its acceleration. Find the time period of SHM(in seconds)

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