Question

A particle executes SHM with amplitude 0.2m and time period 24 sec. The time required by it to move from mean position to a point 0.1 m from the mean position is:

• A. 12 sec
• B. 3 sec
• C. 2 sec
• D. 8 sec

Answer 1

The correct option is C

2 sec

Particle starts from mean position hence equation of motion used will be of sin

$x=Asin\omega t$ $[\varphi =0]$

$0.1=0.2sin\frac{2\pi t}{T}$

$sin\frac{\pi }{6}=sin\frac{\pi t}{12}$

t = 2 sec

Note: Particle starts from mean position use

$x=Asin\omega t$

If particle starts from any position except mean, use

$x=Acos(\omega t+\varphi )$