Question

A particle executes SHM with amplitudes $25$ cm and period $3$ seconds. The minimum time required for it to move between two points $12.5$ cm on either side of the mean position is

• A. 0.25 sec
• B. 0.50 sec
• C. 0.75 sec
• D. 1.00 sec

Answer 1

Answer: (B)

0.50 sec

$Asin\theta =12.5$
$25sin\theta =12.5$
$sin\theta =\frac{1}{2}$
$\theta ={30}^0$
$\therefore 2\theta =60$
Time taken for ${360}^o$ is 3 sec
$\therefore$Time taken for ${60}^0$ is $=\frac{3\times 60}{360}=0.5sec$