A particle executes SHM with the time period of 2 s and amplitude 5cm. Maximum magnitude of its velocity is
A particle executes SHM on a straight line path. The amplitude of oscillation is 2 cm. When the displacement of the particle from the mean position is 1 cm, the numerical value of magnitude of acceleration is equal to the numerical value of magnitude of velocity. The time period of SHM (in Hz) is:
The equation of a particle executing SHM is x=(5m)sin[(π s−1)t+π3]. What is its amplitude, time period, maximum speed and velocity. At t = 1s?