A particle executes simple harmonic motion (amplitude =A) between x=−A and x=+A. The time taken for it to go from 0 to A2 is T1 and to go from A2 to A is T2 . Then
A
T1<T2
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B
T1>T2
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C
T1=T2
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D
T1=2T2
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Solution
The correct option is AT1<T2 Using x=Asin ωt
For x=A2,sin ωT1=12⇒T1=π6ω
For x=A,sin ω(T1+T2)=1⇒T1+T2=π2ω ⇒T2=π2ω−T1=π2ω−π6ω=π3ωi.e.T1<T2