Question

A particle executes simple harmonic motion between x = -A and x=+ A. The time taken for it to go from the mean position, O to $\frac{A}{2}$ is $T_1$ and to go from $\frac{A}{2}$ to A is $T_2$. Then,

• A. T₁<T₂
• B. T₁>T₂
• C. T₁=T2
• D. T₁=2T₂

Answer 1

The correct option is A

T₁<T₂

In SHM, velocity of particle also varies simple harmonically. Speed is more near the mean position and less near the extreme positions. Therefore, the time taken $T_1$ for the particle to go from O to $\frac{A}{2}$ will be less than the time taken to go it from $\frac{A}{2}$ to $A$ or $T_2$