Question

A particle executes simple harmonic motion with frequency $f_1$, the frequency with which kinetic energy oscillates is $f_2$, the frequency with which potential energy oscillates is $f_3$, then $f_1:f_2:f_3$ is

• A. 1 : 2 : 2
• B. 1 : 2 : 4
• C. 1 : 2 : 1
• D. 1 : 1 : 2

Answer 1

The correct option is A 1 : 2 : 2

$Y=A\sin \omega t$ $K.E.=\frac{1}{2}m{w}^2{A}^2{\cos }^2\omega t$ $P.E.=\frac{1}{2}m{\omega }^2{A}^2{\sin }^2\omega t$

$f_1:f_2:f_3=\omega :2\omega :2\omega$

$=1:2:2$