Question

A particle executing SHM has a maximum speed of $0.5m{s}^{-1}$ and maximum acceleration of $1m{s}^{-2}$.

The angular frequency of oscillation is:

• A. $2rad{s}^{-1}$
• B. $0.5rad{s}^{-1}$
• C. $2\pi rad{s}^{-1}$
• D. $0.5\pi rad{s}^{-1}$

Answer 1

The correct option is A $2rad{s}^{-1}$

Maximum velocity, $V_{max}=Aw$

Maximum acceleration, $a_{max}=A{w}^2$

$⟹$ Angular frequency, $w=\frac{a_{max}}{V_{max}}=\frac{1}{0.5}=2$ $rad/s$