Question

A particle executing SHM of amplitude $4cm$ and $T=4s$. The time taken by it to move from positive extreme position to half the amplitude is

• A. $1s$
• B. $\frac{1}{3}s$
• C. $\frac{2}{3}s$
• D. $\sqrt{\frac{3}{2}}s$

Answer 1

The correct option is C $\frac{2}{3}s$

R.E.F image

$W=\frac{2\pi }{T}=\frac{2\pi }{4}=\frac{\pi }{2}$ Using Phalov diagram

$wt=\frac{\pi }{3}$

$\frac{\pi }{2}\left(t\right)=\frac{\pi }{3}$

$\Rightarrow t=\frac{2}{3}s$ Ans