A particle executing SHM of amplitude cm and T=4 s, the time taken by it to move from positive extreme position to half the amplitude is

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\frac{1}{3} s

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\frac{2}{3} s

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\sqrt{\frac{3}{2}}

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Solution

The correct option is C $\frac{2}{3} s$
Hence, option $(C)$ is correct answer.

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Similar questions

4 c m

T = 4 s

S . H . M

4 c m

T = 4 s e c

\frac{\sqrt{3}}{2}

\begin{matrix} A particle is executing SHM of period 4 s. Then the time taken by it to move from extreme position to half the amplitude is \end{matrix}

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