Question

A particle executing SHM with amplitude A has maximum velocity $v_0$. Its speed at displacement $\frac{A}{\sqrt{2}}$ will be

• A. $\frac{v_0}{\sqrt{2}}$
• B. $v_0$
• C. Zero
• D. $\frac{v_0}{\sqrt{3}}$

Answer 1

The correct option is A $\frac{v_0}{\sqrt{2}}$

$v=w\sqrt{A^2-X^2}$ $v_0=Aw$

$=\frac{v_0}{A}\sqrt{A^2-\frac{A^2}{2}}$

$=\frac{v_0}{\text{/}A}\frac{\text{/}A}{\sqrt{2}}$

$v=\frac{v_0}{\sqrt{2}}$