Question

A particle experiences a fixed acceleration for $6$ seconds after starting from rest. It cover a distance of $s_1$ in first two seconds, $s_2$ in the next 2 seconds and $s_3$ in the last 2 seconds then $s_3:s_2:s_1$ is

• A. $1:3:5$
• B. $5:3:1$
• C. $1:2:3$
• D. $4:3:2:1$

Answer 1

Answer: (B)

$5:3:1$

Using the equations
$s=ut+\frac{1}{2}a{t}^{2}v=u+at$
We get
For $t=0$ to $t=2$
$u=0m/ss=2am$
For $t=2$ to $t=4$
$u=2am/ss=6am$
For $t=4$ to $t=6$
$u=4am/ss=10am$