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A particle fo...

Question

A particle follows oscillating motion along line. P.E. of particle varies as $U = x^{2} - 4 x + 29$ . Locate mean position of particle.

A

x = 4

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B

x = 5

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C

x = 7

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D

x = 2

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Solution

The correct option is D x = 2
At mean position, P.E = minimum

$V = x^{2} - 4 x + 29$

$= x^{2} - 4 x + 4 + 25$

$V = (x - 2)^{2} + 25$

$V_{m i n} = 25$ at $x = 2$

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