A particle follows uniform motion along line from P $(2, 4, 6)$ to Q $(4, 8, 2)$ with a speed of $12$ m/s. Find velocity vector of the particle.

2^i + 4^j - 4^k

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4^i + 8^j - 8^k

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12 (2^i + 4^j - 4^k)

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Solution

The correct option is B $4^i + 8^j - 8^k$
$\to v = (12 m / s) unit vetcor$
$= 12 \frac{2^i + 4^j + 4^k}{\sqrt{2^{2} + 4^{2} + 4^{2}}}$
$=12{2^i+4^j−4^k}6$
$\to v = 4^i + 8^j - 8^k$

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A particle follows uniform motion along line from P (2,4,6) to Q(4,8,2) with a speed of 12 m/s. Find velocity vector of the particle.

The correct option is B 4^i+8^j−8^k→v=(12 m/s)unit vetcor =122^i+4^j+4^k√22+42+42 =12{2^i+4^j−4^k}6 →v=4^i+8^j−8^k

A particle follows uniform motion along line from P $(2, 4, 6)$ to Q $(4, 8, 2)$ with a speed of $12$ m/s. Find velocity vector of the particle.

The correct option is B $4^i + 8^j - 8^k$
$\to v = (12 m / s) unit vetcor$
$= 12 \frac{2^i + 4^j + 4^k}{\sqrt{2^{2} + 4^{2} + 4^{2}}}$
$=12{2^i+4^j−4^k}6$
$\to v = 4^i + 8^j - 8^k$