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Question

A particle hanging from a spring stretches by 1cm at earth's surface. At a point 800km above earths surface, the same spring stretches by the same particle (Radius of earth R=6400km) is:

A
1cm
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B
0.75cm
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C
1.2cm
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D
1.4cm
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Solution

The correct option is B 0.75cm
Given,
Let the mass of the body be m, and the gravitational acceleration go stretches in spring 1cm,
The height above the earth's surface=800Km
Radius of the earth R=6400Km
So,
mgo=kx1..................(1)
We know that,
g=go(12hR)
mg=kx2................(2)
from equaiton(1) and (2)
43=1x2
So x2=0.75cm


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