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Question

A particle has an angular momentum L and a linear momentum P about a reference point O. If r is the position vector of particle with respect to reference point, then identify correct option.

A
L=P×r
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B
|L×P|=LP
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C
L×P=0
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D
None of these
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Solution

The correct option is B |L×P|=LP
We know,
L=r×P
L being the cross -product vector, It will be to the plane containing both vectors P and r
Angle between vectors L and P will be 90.
|L×P|=LPsin90=LP
However, L.P=LPcos90=0
Option (b) is correct.

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