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Question

A particle has an initial velocity 3i^+4j^ and an acceleration of 0.4i^+0.3j^. Its speed after 10s is


A

10units

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B

7units

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C

72units

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D

8.5units

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Solution

The correct option is C

72units


Step 1: Given data

Initial velocity, u=3i^+4j^

Acceleration, a=0.4i^+0.3j^

Time, t=10s

Step 2: Find Final velocity

Final velocity (v) is given by

using the first equation of motion,

v=u+atv=3i^+4j^+(0.4i^+0.3j^)10v=7i^+7j^

V=72+72V=72units

Hence, option C is correct.


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