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Question

A particle has an initial velocity of 3^i+4^j and an acceleration of 0.4^i+0.3^j. The magnitude of its velocity after 10 s is

A
10 units
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B
72 units
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C
7 units
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D
8.5 units
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Solution

The correct option is B 72 units
The initial velocity is give as Vi=3ˆi+4ˆj
the acceleration is a a=0.4ˆi+0.3ˆj
and the time elapsed is y=10s
now final velocity after 10s is Vf=(3ˆi+4ˆj)m/s+10s(0.4ˆi+0.3ˆj)m/s
Vf=7ˆi+7ˆj
V=(7ˆi)2+(7ˆj)2=72
Hence,
option (B) is correct answer.

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