-8203-a particle has displacement equations nbsp- 1- Xa - 2t-7 2- Xb-3t-2 -2t-6 3- Xc-5t-2-4t -Which of them has uniform acceleration nbsp-

Dear Student , Here in this case , Xa=2t+7 #8658;dXadt=2 #8658;d2Xadt2=0Xb=3t2+2t+6 #8658;dXbdt=6t+2 #8658;d2Xbdt2=6 #8594;Uniform #160;acceleration ...

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Standard IX

Physics

Acceleration

#8203;a parti...

Question

a particle has displacement equations 1) Xa = 2t+7 2) Xb=3t^2 +2t+6 3) Xc=5t^2+4t .Which of them has uniform acceleration

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Solution

Dear Student ,
Here in this case ,
$X_{a} = 2 t + 7 \Rightarrow \frac{d X_{a}}{d t} = 2 \Rightarrow \frac{d^{2} X_{a}}{d t^{2}} = 0 X_{b} = 3 t^{2} + 2 t + 6 \Rightarrow \frac{d X_{b}}{d t} = 6 t + 2 \Rightarrow \frac{d^{2} X_{b}}{d t^{2}} = 6 \to U n i f o r m a c c e l e r a t i o n X_{c} = 5 t^{2} + 4 t \Rightarrow \frac{d X_{c}}{d t} = 10 t + 4 \Rightarrow \frac{d^{2} X_{c}}{d t^{2}} = 10 \to U n i f o r m a c c e l e r a t i o n$

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​a particle has displacement equations 1) Xa = 2t+7 2) Xb=3t^2 +2t+6 3) Xc=5t^2+4t .Which of them has uniform acceleration

Dear Student , Here in this case , Xa=2t+7⇒dXadt=2⇒d2Xadt2=0Xb=3t2+2t+6⇒dXbdt=6t+2⇒d2Xbdt2=6→Uniform accelerationXc=5t2+4t⇒dXcdt=10t+4⇒d2Xcdt2=10→Uniform acceleration Regards

a particle has displacement equations 1) Xa = 2t+7 2) Xb=3t^2 +2t+6 3) Xc=5t^2+4t .Which of them has uniform acceleration