A particle has initial velocity (2^i+3^j) and acceleration (0.3^i+0.2^j). The magnitude of velocity after 10s will be
A
5units
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B
9units
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C
9√2units
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D
5√2units
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Solution
The correct option is D5√2units Let the velocity after 10s be v v=vx^i+vy^j v=(ux+axt)^i+(ux+ayt)^j =(2+0.3(10))^i+(3+0.2(10))^j =5^i+5^j v=√52+52 =5√2units