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Question

A particle has initial velocity 4i+4j ms1 and an acceleration 0.4i ms2, at what time will its speed be 5 ms1?

A
2.5 s
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B
17.5 s
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C
s
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D
8.5 s
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Solution

The correct option is B 17.5 s
A,B
Vy=4m/s(1)

Vx=40.4t(2)

Speed, V=V2x+V2y(3)

5=42+V2x

Vx=±3(4)

(4) in (2) 3=40.4t

t=2.5s

also, 3=40.4t

t=17.5s

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