A particle has initial velocity, →v=3^i+4^j and a constant force →F=4^i−3^j acts on it. The path of the particle can be:
A
straight line
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B
parabolic
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C
circular
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D
hyperbolic
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Solution
The correct option is B circular As it can be seen easily, the Force vector is constant and perpendicular to the velocity vector (dot product is zero). Thus such a path would be circular motion.