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Question

A particle has initial velocity (2i+3j) and acceleration (0.3i+0.2j). The magnitude of velocity after 10 seconds will be

A
5 units
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B
9 units
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C
92 units
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D
52 units
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Solution

The correct option is D 52 units
Velocity after time t=(ux+axt)i+(uy+ayt)j
a=[2+0.3(10)]i+[3+0.2(10)]j=5i+5j

So, The magnitude of velocity after 10 seconds will be
|a|=52+52=52 units.
Therefore, D is correct option.

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