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Question

A particle has initial velocity v=3i+4j, and a constant force F=4i+3j acts on a particle. The path of the particle is

A
Straight line
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B
Parabolic
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C
Circular
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D
Elliptical
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Solution

The correct option is B Parabolic
Correct option is (B) As we know:
s=ut+1/2at2(1)
so, Vx=3 m/s and ax=4 m
m= mass putting in eq. (1)
x=3t2mt2
Similarly; Vy=4 m/s and ay=3/m

y=4t+32mt2

Hence here x and y are related as y2=cx;
where c is constant so, it represents parabola

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