A particle has potential energy dependent on its position on the x axis, represented by the function U(x)=e2x+1 for all real values of x, where U(x) and x are given in standard units. The force it feels at position x=1 is closest to
[Take e=2.72]
A
8.39N
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B
−8.39N
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C
14.8N
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D
−14.8N
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Solution
The correct option is D−14.8N The potential energy of the particle U(x)=e2x+1
Thus force acting on the particle F=−dU(x)dx=−2e2xN ⇒F|x=1=−2e2=−2×(2.72)2=−14.8N