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Question

A particle. has the position vectorr=^i2^j+k and the linear momentum p=2^i^j+^k. Its angular momentum about the origin is

A
^i+^j3^k
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B
^i+^j+3^k
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C
^i^j+3^k
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D
^i^j5^k
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E
^i+^j+5^k
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Solution

The correct option is B ^i+^j+3^k
Given,
r=^i2^j+^k
p=2^i^j+^k
Angular momentum
J=r×p
=(^i2^j^k)×(2^i^j+^k)
J=^i(2+1)^j(12)+^k(1+4)
J=^i+^j+3^k

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