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Question

A particle having a mass of 102 kg carries a charge of 5×108 C. The particle is given an initial horizontal velocity of 105ms1 in the presence of electric field E and magnetic field B. To keep the particle moving in a horizontal direction, it is necessary that

(i) B should be perpendicular to the direction of velocity and E should be along the direction of velocity.
(ii) Both B and E should be along the direction of velocity.
(iii) Both B and E are mutually perpendicular and perpendicular to the direction of velocity.
(iv) B should be along the direction of velocity and E should be perpendicular to the direction of velocity.
Which one of the following pairs of statements is possible

A
(i) and (iii)
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B
(iii) and (iv)
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C
(ii) and (iii)
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D
(ii) and (iv)
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Solution

The correct option is C (ii) and (iii)
Case 1:- In figure 1 if FE=FB particle will always move in a straight line.(option (iii))
Case 2:- In figure 2 particle will always move in a straight line.(option (ii))
337536_306629_ans_04da26a209ab4b3a9318577eba6d670f.png

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