Question

A particle having charge $100$ times that of an electron is revolving in a circular path of radius $0.8m$ with one rotation per second.The magnetic field produced at the centre is

• A. ${10}^{-7}/{\mu }_0$
• B. ${10}^{-17}{\mu }_0$
• C. ${10}^{-6}{\mu }_0$
• D. ${10}^{-15}{\mu }_0$

Answer 1

Answer: (B)

${10}^{-17}{\mu }_0$

$B=\frac{{\mu }_{0}i}{2r}$
$=\frac{{\mu }_0\left(qf\right)}{2r}$
$=\frac{{\mu }_0(100\times 1\cdot 6\times {10}^{-19}\times 1)}{2\times 0\cdot 8}$
$={10}^{-17}{\mu }_{0}T$