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Question

# A particle having charge 100 times that of an electron is revolving in a circular path of radius 0.8 m with one rotation per second. The magnetic field produced at the centre of the particle is :

A
1017μ0
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B
1011μ0
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C
107μ0
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D
103μ0
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Solution

## The correct option is A 10−17μ0Here change on particle q=ne=100e=100×1.6×10−13C=1.6×10−17CRadius of circular path r = 0.8 mTime period T = 1 rotation/sThe current associated with the particle is i=chargetime=1.6×10−17AMagnetic field produced at the centre of the coil is given by B=μ0×i2r=μ0×1.6×10−172×0.8=10−17μ0

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