A particle having initial velocity 10m/s is moving with constant acceleration 4m/s2. The particle is moving in a straight line. Find the distance travelled by the particle in 7th second of its motion
A
10m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
28m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
36m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D36m Given, u=10m/s,a=4m/s2,n=7
As we know that the distance travelled by a particle in nth second is given as Sn=u+12a(2n−1) ⇒S7th=10+12×4[2×7−1] ⇒S7th=10+2(13)=36m