wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle having mass 10g oscillates according to the equation x=(2.0cm) sin[(100s1)t+π6]. Find the spring constant


A

200 kg/s2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

100 kg/s2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

10,000 kg/s2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

Not enough information given

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

100 kg/s2


A general sinusoidal, oscillation of amplitude A, angular frequency ω and at a phase ψ is given as

x(t)=A sin (ω t+ψ),

Compare this with the equation under discussion

x=[(0.2cm)sin(100s1)t+π6]

It is clear from a comparison, that

A=0.2 cm=0.002 m

ω=100s1, andψ=π6

We know that for oscillations in a spring mass system, the spring constant is related to the mass m and ω as

k=mω2

The mass is given to us, viz. m=10g=0.01kg

The k=[0.01× 1002]kgs2

=100kgs2

Hence correct option is (b).


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The General Expression
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon