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Magnetic Field Due to Finite Wire

A particle ha...

Question

A particle having mass m and charge q is released from the origin in a region in which electric field and
magnetic fields are given by $B = - B_{0}^k$ and $E = E^k .$ Find the speed of the particle as a function of its z
coordinate.

\sqrt{\frac{q E z}{m}}

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\sqrt{\frac{2 (q v B + q E) z}{m}}

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\sqrt{\frac{(- q v B + q E) 2 z}{m}}

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\sqrt{\frac{2 q E z}{m}}

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Solution

The correct option is D $\sqrt{\frac{2 q E z}{m}}$
$v^{2} = 2 a z a = \frac{q E}{m} o r v = \sqrt{\frac{2 q E z}{m}}$

Suggest Corrections

Similar questions

m

q

\to B = B_{0}^j

\to E = E_{0}^k

z -

\vec{B} = - B_{0} \vec{j} and \vec{E} = E_{0} \vec{k}

A particle having mass m and charge q is released from the origion in a region in which electric field and magnetic field are given by

$\to B = - B_{0} \to J$ and $\to E = E_{o} - \to K .$

Find the speed of the particle as a function of its z-coordinate.

m

q

\to B = - B_{0}^j

\to E = E_{0}^k

z -

m

q

\to B = B_{0}^j

\to E = E_{0}^k

z -

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