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Question

A particle having mass m is projected with a speed v at an angle α with the horizontal ground. Find the torque of the weight of the particle about the point of projection when the particle reaches the ground.

A
2mv2sin2α
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B
mv2sin2α2
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C
mv2sin2α
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D
0
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Solution

The correct option is C mv2sin2α

As we know,
τ=r×F
τ=rF
r=Range=v2sin2αg
Hence, τ=v2sin2αg×mg
τ=mv2sin2α

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