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Byju's Answer
Standard IX
Physics
Distance-Time Graphs
A particle in...
Question
A particle in seen at x=0 at t=0. The acceleration of the particle depends on time as acceleration = (2m/s^3)t + (1m/s^2)along x axis Then If the particle is at rest at the origin at moment t= 0 sec,then t=6sec it's velocity will be ?
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Similar questions
Q.
A particle moves along x-axis and its acceleration at any time
t
is
a
=
2
s
i
n
(
π
t
)
, where
t
is in seconds and
a
is in
m
/
s
2
. The initial velocity of particle (at time
t
=
0
) is
u
=
0
.
Then the magnitude of displacement (in meters) by the particle from time
t
=
0
to
t
=
t
will be
Q.
A particle moves along x-axis and its acceleration at any time
t
is
a
=
2
s
i
n
(
π
t
)
, where
t
is in seconds and
a
is in
m
/
s
2
. The initial velocity of particle (at time
t
=
0
) is
u
=
0
.
Then the distance travelled (in meters) by the particle from time
t
=
0
to
t
=
t
will be
Q.
Velocity in
m
/
s
of a particle moving along
x
−
axis varies with time as
v
=
(
10
+
5
t
−
t
2
)
. At time
t
=
0
,
x
=
0.
Acceleration of particle at
t
=
2
s
is
x
m
/
s
2
, then value of
x
is
Q.
A particle moves along
x
-axis. it is at rest, at
t
=
0
,
x
=
0
and comes to rest at
t
=
1
,
x
=
1
. If
α
denotes instantaneous acceleration, then
Q.
A particle is moving along positive
x
-axis and at
t
=
0
, the particle is at
x
=
0
. The acceleration of the particle is a function of time. The acceleration at any time
t
is given by
a
=
2
(
1
–
[
t
]
)
where
[
t
]
is the greatest integer function . Assuming that the particle is at rest initially, the average speed of the particle for the interval
t
=
0
s
to
t
=
4
s
is
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