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Question

A particle in SHM is described by the displacement

equation x(t) = A cos ( ωt+θ) . If the initial (t = 0)

position of the particle is 1 cm and its initial

velocity is π cm/s, what is its amplitude?

The angular frequency of the particle is πs1


A

1 cm

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B

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C

2 cm

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D

2.5 cm

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Solution

The correct option is

D



Given v = π cm/sec , x = 1 cm and ω=πs1

using v = ωa2x2π=πa21

1=a21a=2cm.


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