A particle, initially at rest, moves with an acceleration $5 m s^{- 2}$ for $5 s$ . Find the distance travelled in $4 s$ .

30 m

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40 m

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50 m

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60 m

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Solution

The correct option is A $40 m$
$u = 0$
$a = 5 m s^{- 2}$
As it undergoes acceleration for $5 s$ , the distance travelled in $4 s$ is due to an accelerated motion.
$t = 4 s$
$∴ s = u t + \frac{1}{2} a t^{2} = (0 \times 4) + (\frac{1}{2} \times 5 \times 4^{2}) = 40 m$

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A particle, initially at rest, moves with an acceleration 5ms−2 for 5s. Find the distance travelled in 4s.

The correct option is A 40mu=0a=5 ms−2As it undergoes acceleration for 5 s, the distance travelled in 4 s is due to an accelerated motion.t=4 s∴s=ut+12at2=(0×4)+(12×5×42)=40 m

A particle, initially at rest, moves with an acceleration $5 m s^{- 2}$ for $5 s$ . Find the distance travelled in $4 s$ .

The correct option is A $40 m$
$u = 0$
$a = 5 m s^{- 2}$
As it undergoes acceleration for $5 s$ , the distance travelled in $4 s$ is due to an accelerated motion.
$t = 4 s$
$∴ s = u t + \frac{1}{2} a t^{2} = (0 \times 4) + (\frac{1}{2} \times 5 \times 4^{2}) = 40 m$