A particle initially at rest, moves with an acceleration $5 m s^{- 2}$ for $5 s$ . Find the distance traveled in $5 s$ .

25 m

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125 m

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12.5 m

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62.5 m

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Solution

The correct option is D $62.5 m$
Distance travelled in $t = 5 s$ ,
$s = u t + \frac{1}{2} a t^{2} = 0 \times 5 + \frac{1}{2} \times 5 \times (5)^{2}$
$= 62.5 m$

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A particle initially at rest, moves with an acceleration 5 ms−2 for 5 s. Find the distance traveled in 5 s.

The correct option is D 62.5 mDistance travelled in t=5 s,s=ut+12at2=0×5+12×5×(5)2=62.5m

A particle initially at rest, moves with an acceleration $5 m s^{- 2}$ for $5 s$ . Find the distance traveled in $5 s$ .

The correct option is D $62.5 m$
Distance travelled in $t = 5 s$ ,
$s = u t + \frac{1}{2} a t^{2} = 0 \times 5 + \frac{1}{2} \times 5 \times (5)^{2}$
$= 62.5 m$